(a) Evaluate \(h(x) = \dfrac{\tan x - x}{x^3}\) for \(x = 1, 0.5, 0.1, 0.05, 0.01\), and \(0.005\).
(b) Guess the value of \(\operatorname*{lim}\limits_{x \rightarrow 0} \dfrac{\tan x - x}{x^3}\).
(c) Evaluate \(h(x)\) for successively smaller values of \(x\) until you finally reach 0 values. Are you still confident about your guess? Explain.
(d) Graph \(h\) in the viewing rectangle \([-1, 1]\) by \([0, 1]\) and zoom in toward the point where the graph crosses the \(y\)-axis. What do you notice? Compare with your results in part (c).
(a) Find the vertical asymptotes of the function \(y = \dfrac{x^2 + 1}{3x - 2x^2}\).
(b) Confirm by graphing the function.
Question 3 of 20
| Limits - Numerical
· Level 2
Guess the value of the limit (if it exists) by evaluating the function at the given numbers (correct to six decimal places).
\(\operatorname*{lim}\limits_{h \rightarrow 0} \dfrac{(2 + h)^5 - 32}{h}\),
\(h = \pm 0.5, \pm 0.1, \pm 0.01, \pm 0.001, \pm 0.0001\)
Consider the function \(f(x) = \tan\left(\dfrac{1}{x}\right)\).
(a) Show that \(f(x) = 0\) for \(x = \dfrac{1}{\pi}, \dfrac{1}{2 \pi}, \dfrac{1}{3 \pi}, \cdots\)
(b) Show that \(f(x) = 1\) for \(x = \dfrac{4}{\pi}, \dfrac{4}{5 \pi}, \dfrac{4}{9 \pi}, \cdots\)
(c) What can you conclude about \(\operatorname*{lim}\limits_{x \rightarrow 0^+} \tan\left(\dfrac{1}{x}\right)\)?
Question 5 of 20
| Limits - Definition
· Level 1
Explain in your own words what is meant by the equation \(\operatorname*{lim}\limits_{x \rightarrow 2} f(x) = 5\). Is it possible for this statement to be true and yet \(f(2) = 3\)? Explain.
Question 6 of 20
| Continuity - IVT
· Level 3
Use the Intermediate Value Theorem to show that there is a solution of the equation in the given interval.
\(\dfrac{2}{x} = x - \sqrt{x}\), \((2, 3)\)
Explain, using Theorems 4, 5, 7, and 9, why the function is continuous at every number in its domain. State the domain.
\(B(u) = \sqrt{3u - 2} + \sqrt{2u - 3}\)
Explain why the function is discontinuous at the given number \(a\). Sketch the graph of the function.
\(f(x) = \begin{cases} \cos x & \quad \text{if } x < 0 \\ 0 & \quad \text{if } x = 0 \\ 1 - x^2 & \quad \text{if } x > 0 \end{cases}\), \(a = 0\)
Question 9 of 20
| Continuity - IVT
· Level 3
If \(f(x) = x^2 + 10 \sin x\), show that there is a number \(c\) such that \(f(c) = 1000\).
Question 10 of 20
| Continuity - Proof
· Level 4
Suppose \(f\) and \(g\) are continuous functions such that \(g(2) = 6\) and \(\operatorname*{lim}\limits_{x \rightarrow 2} [3 f(x) + f(x) g(x)] = 36\). Find \(f(2)\).
Question 11 of 20
| Differentiation: Composite, Implicit, and Inverse Functions
· Level 4
Find the given derivative by finding the first few derivatives and observing the pattern that occurs.
\(D^{103} \cos 2x\)
Question 12 of 20
| Differentiation: Composite, Implicit, and Inverse Functions
· Level 2
Write the composite function in the form \(f(g(x))\). [Identify the inner function \(u = g(x)\) and the outer function \(y = f(u)\).] Then find the derivative \(\dfrac{d y}{d x}\).
\(y = \tan(x^2)\)
Question 13 of 20
| Differentiation: Composite, Implicit, and Inverse Functions
· Level 3
\( A(t) = \dfrac{1}{(\cos t + \tan t)^2} \)
Question 14 of 20
| Differentiation: Composite, Implicit, and Inverse Functions
· Level 3
\( G(z) = (1 - 4z)^2 \sqrt{z^2 + 1} \)
Question 15 of 20
| Differentiation: Composite, Implicit, and Inverse Functions
· Level 4
The function \(f(x) = \sin(x + \sin 2x)\), \(0 \leq x \leq \pi\), arises in applications to frequency modulation (FM) synthesis.
(a) Use a graph of \(f\) produced by a calculator or computer to make a rough sketch of the graph of \(f'\).
(b) Calculate \(f'(x)\) and use this to graph \(f'\). Compare with your sketch in part (a).
Question 16 of 20
| Differentiation: Composite, Implicit, and Inverse Functions
· Level 3
\(y \sin 2x = x \cos 2y\), \(\quad \left(\dfrac{\pi}{2}, \dfrac{\pi}{4}\right)\)
Question 17 of 20
| Differentiation: Composite, Implicit, and Inverse Functions
· Level 3
If \(f(x) + x^2 [f(x)]^3 = 10\) and \(f(1) = 2\), find \(f'(1)\).
Question 18 of 20
| Differentiation: Composite, Implicit, and Inverse Functions
· Level 4
Two curves are orthogonal if their tangent lines are perpendicular at each point of intersection. Show that the given families of curves are orthogonal trajectories of each other; that is, every curve in one family is orthogonal to every curve in the other family. Sketch both families of curves on the same axes.
\(x^2 + y^2 = r^2\), \(\quad a x + b y = 0\)
Question 19 of 20
| Differentiation: Composite, Implicit, and Inverse Functions
· Level 4
Use implicit differentiation to find \(\dfrac{d y}{d x}\) for the equation \(\dfrac{x}{y} = y^2 + 1\) (where \(y \neq 0\)). Then show that you get the same answer when you perform implicit differentiation on the equivalent equation \(x = y^3 + y\) (where \(y \neq 0\)).
Question 20 of 20
| Differentiation: Composite, Implicit, and Inverse Functions
· Level 3
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Graphing Calculator
Reference Sheet
Area & Circumference
Circle$A = \pi r^2$, $C = 2\pi r$
Rectangle$A = lw$
Triangle$A = \tfrac{1}{2}bh$
Trapezoid$A = \tfrac{1}{2}(b_1+b_2)h$
Volume
Box$V = lwh$
Cylinder$V = \pi r^2 h$
Sphere$V = \tfrac{4}{3}\pi r^3$
Cone$V = \tfrac{1}{3}\pi r^2 h$
Pyramid$V = \tfrac{1}{3}lwh$
Triangles
Pythagorean Thm$a^2 + b^2 = c^2$
30-60-90sides: $1,\, \sqrt{3},\, 2$
45-45-90sides: $1,\, 1,\, \sqrt{2}$
Triangle Anglessum $= 180°$
Other Facts
Circle Degrees$360° = 2\pi \text{ rad}$
Exterior Angle= sum of non-adjacent interior angles
The number of degrees of arc in a circle is 360. The number of radians of arc in a circle is $2\pi$.
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