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Stewart 9th - 1.5, 1.8, 2.5, 2.6 (20Q) 0/20
Question 1 of 20   |  Limits - Investigation  · Level 4
(a) Evaluate \(h(x) = \dfrac{\tan x - x}{x^3}\) for \(x = 1, 0.5, 0.1, 0.05, 0.01\), and \(0.005\).
(b) Guess the value of \(\operatorname*{lim}\limits_{x \rightarrow 0} \dfrac{\tan x - x}{x^3}\).
(c) Evaluate \(h(x)\) for successively smaller values of \(x\) until you finally reach 0 values. Are you still confident about your guess? Explain.
(d) Graph \(h\) in the viewing rectangle \([-1, 1]\) by \([0, 1]\) and zoom in toward the point where the graph crosses the \(y\)-axis. What do you notice? Compare with your results in part (c).
Question 2 of 20   |  Limits - Vertical Asymptotes  · Level 2
(a) Find the vertical asymptotes of the function \(y = \dfrac{x^2 + 1}{3x - 2x^2}\).
(b) Confirm by graphing the function.
Question 3 of 20   |  Limits - Numerical  · Level 2
Guess the value of the limit (if it exists) by evaluating the function at the given numbers (correct to six decimal places). \(\operatorname*{lim}\limits_{h \rightarrow 0} \dfrac{(2 + h)^5 - 32}{h}\), \(h = \pm 0.5, \pm 0.1, \pm 0.01, \pm 0.001, \pm 0.0001\)
Question 4 of 20   |  Limits - Investigation  · Level 4
Consider the function \(f(x) = \tan\left(\dfrac{1}{x}\right)\).
(a) Show that \(f(x) = 0\) for \(x = \dfrac{1}{\pi}, \dfrac{1}{2 \pi}, \dfrac{1}{3 \pi}, \cdots\)
(b) Show that \(f(x) = 1\) for \(x = \dfrac{4}{\pi}, \dfrac{4}{5 \pi}, \dfrac{4}{9 \pi}, \cdots\)
(c) What can you conclude about \(\operatorname*{lim}\limits_{x \rightarrow 0^+} \tan\left(\dfrac{1}{x}\right)\)?
Question 5 of 20   |  Limits - Definition  · Level 1
Explain in your own words what is meant by the equation \(\operatorname*{lim}\limits_{x \rightarrow 2} f(x) = 5\). Is it possible for this statement to be true and yet \(f(2) = 3\)? Explain.
Question 6 of 20   |  Continuity - IVT  · Level 3
Use the Intermediate Value Theorem to show that there is a solution of the equation in the given interval. \(\dfrac{2}{x} = x - \sqrt{x}\), \((2, 3)\)
Question 7 of 20   |  Continuity - Domain/Theorems  · Level 3
Explain, using Theorems 4, 5, 7, and 9, why the function is continuous at every number in its domain. State the domain. \(B(u) = \sqrt{3u - 2} + \sqrt{2u - 3}\)
Question 8 of 20   |  Continuity - Discontinuity Analysis  · Level 3
Explain why the function is discontinuous at the given number \(a\). Sketch the graph of the function. \(f(x) = \begin{cases} \cos x & \text{if } x < 0 \\ 0 & \text{if } x = 0 \\ 1 - x^2 & \text{if } x > 0 \end{cases}\), \(a = 0\)
Question 9 of 20   |  Continuity - IVT  · Level 3
If \(f(x) = x^2 + 10 \sin x\), show that there is a number \(c\) such that \(f(c) = 1000\).
Question 10 of 20   |  Continuity - Proof  · Level 4
Suppose \(f\) and \(g\) are continuous functions such that \(g(2) = 6\) and \(\operatorname*{lim}\limits_{x \rightarrow 2} [3 f(x) + f(x) g(x)] = 36\). Find \(f(2)\).
Question 11 of 20   |  Chain Rule - Pattern/nth Derivative  · Level 4
Find the given derivative by finding the first few derivatives and observing the pattern that occurs. \(D^{103} \cos 2x\)
Question 12 of 20   |  Chain Rule - Composite Identification  · Level 2
Write the composite function in the form \(f(g(x))\). [Identify the inner function \(u = g(x)\) and the outer function \(y = f(u)\).] Then find the derivative \(\dfrac{d y}{d x}\). \(y = \tan(x^2)\)
Question 13 of 20   |  Chain Rule - Basic  · Level 3
Find the derivative of the function. \(A(t) = \dfrac{1}{(\cos t + \tan t)^2}\)
Question 14 of 20   |  Chain Rule - Product/Quotient Combo  · Level 3
Find the derivative of the function. \(G(z) = (1 - 4z)^2 \sqrt{z^2 + 1}\)
Question 15 of 20   |  Chain Rule - Graph Analysis  · Level 4
The function \(f(x) = \sin(x + \sin 2x)\), \(0 \leq x \leq \pi\), arises in applications to frequency modulation (FM) synthesis.
(a) Use a graph of \(f\) produced by a calculator or computer to make a rough sketch of the graph of \(f'\).
(b) Calculate \(f'(x)\) and use this to graph \(f'\). Compare with your sketch in part (a).
Question 16 of 20   |  Implicit Diff - Tangent Lines  · Level 3
Use implicit differentiation to find an equation of the tangent line to the curve at the given point. \(y \sin 2x = x \cos 2y\), \(\quad \left(\dfrac{\pi}{2}, \dfrac{\pi}{4}\right)\)
Question 17 of 20   |  Implicit Diff - Given Values  · Level 3
If \(f(x) + x^2 [f(x)]^3 = 10\) and \(f(1) = 2\), find \(f'(1)\).
Question 18 of 20   |  Implicit Diff - Orthogonal Trajectories  · Level 4
Two curves are orthogonal if their tangent lines are perpendicular at each point of intersection. Show that the given families of curves are orthogonal trajectories of each other; that is, every curve in one family is orthogonal to every curve in the other family. Sketch both families of curves on the same axes. \(x^2 + y^2 = r^2\), \(\quad a x + b y = 0\)
Question 19 of 20   |  Implicit Diff - Applied/Proof  · Level 4
Use implicit differentiation to find \(\dfrac{d y}{d x}\) for the equation \(\dfrac{x}{y} = y^2 + 1\) (where \(y \neq 0\)). Then show that you get the same answer when you perform implicit differentiation on the equivalent equation \(x = y^3 + y\) (where \(y \neq 0\)).
Question 20 of 20   |  Implicit Diff - Tangent Lines  · Level 3
Use implicit differentiation to find an equation of the tangent line to the curve at the given point. \(y^2(6 - x) = x^3\), \(\quad (2, \sqrt{2})\) (cissoid of Diocles)

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Reference Sheet

Area & Circumference

Circle$A = \pi r^2$,  $C = 2\pi r$
Rectangle$A = lw$
Triangle$A = \tfrac{1}{2}bh$
Trapezoid$A = \tfrac{1}{2}(b_1+b_2)h$

Volume

Box$V = lwh$
Cylinder$V = \pi r^2 h$
Sphere$V = \tfrac{4}{3}\pi r^3$
Cone$V = \tfrac{1}{3}\pi r^2 h$
Pyramid$V = \tfrac{1}{3}lwh$

Triangles

Pythagorean Thm$a^2 + b^2 = c^2$
30-60-90sides: $1,\, \sqrt{3},\, 2$
45-45-90sides: $1,\, 1,\, \sqrt{2}$
Triangle Anglessum $= 180°$

Other Facts

Circle Degrees$360° = 2\pi \text{ rad}$
Exterior Angle= sum of non-adjacent interior angles

The number of degrees of arc in a circle is 360. The number of radians of arc in a circle is $2\pi$.

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