Stewart Section 9.3: Separable Equations

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Stewart Section 9.3: Separable Equations 0/54
1 Separable Equations - Solve · Level 2
\( \dfrac{d y}{d x} = 3x^2 y^2 \)
2 Separable Equations - Solve · Level 2
\( \dfrac{d y}{d x} = x \sqrt{y} \)
3 Separable Equations - Solve · Level 2
\( x y y' = x^2 + 1 \)
4 Separable Equations - Solve · Level 2
\( y' + x e^y = 0 \)
5 Separable Equations - Solve · Level 3
\( (e^y - 1)y' = 2 + \cos x \)
6 Separable Equations - Solve · Level 3
\( \dfrac{d u}{d t} = \dfrac{1 + t^4}{u t^2 + u^4 t^2} \)
7 Separable Equations - Solve · Level 3
\( \dfrac{d \theta}{d t} = \dfrac{t \sec \theta}{\theta e^{t^2}} \)
8 Separable Equations - Solve · Level 3
\( \dfrac{d H}{d R} = \dfrac{R H^2 \sqrt{1 + R^2}}{\ln H} \)
9 Separable Equations - Solve · Level 3
\( \dfrac{d p}{d t} = t^2 p - p + t^2 - 1 \)
10 Separable Equations - Solve · Level 3
\( \dfrac{d z}{d t} + e^{t + z} = 0 \)
11 Separable Equations - IVP · Level 3
Find the solution of the differential equation that satisfies the given initial condition. \( \dfrac{d y}{d x} = x e^y \), \(\quad y(0) = 0\)
12 Separable Equations - IVP · Level 3
Find the solution of the differential equation that satisfies the given initial condition. \( \dfrac{d y}{d x} = \dfrac{x \sin x}{y} \), \(\quad y(0) = -1\)
13 Separable Equations - IVP · Level 3
Find the solution of the differential equation that satisfies the given initial condition. \( \dfrac{d u}{d t} = \dfrac{2t + \sec^2 t}{2u} \), \(\quad u(0) = -5\)
14 Separable Equations - IVP · Level 3
Find the solution of the differential equation that satisfies the given initial condition. \(x + 3y^2 \sqrt{x^2 + 1} \dfrac{d y}{d x} = 0\), \(\quad y(0) = 1\)
15 Separable Equations - IVP · Level 3
Find the solution of the differential equation that satisfies the given initial condition. \(x \ln x = y(1 + \sqrt{3 + y^2}) y'\), \(\quad y(1) = 1\)
16 Separable Equations - IVP · Level 3
Find the solution of the differential equation that satisfies the given initial condition. \( \dfrac{d P}{d t} = \sqrt{P t} \), \(\quad P(1) = 2\)
17 Separable Equations - IVP · Level 3
Find the solution of the differential equation that satisfies the given initial condition. \(y' \tan x = a + y\), \(\quad y\left(\dfrac{\pi}{3}\right) = a\), \(\quad 0 < x < \dfrac{\pi}{2}\)
18 Separable Equations - IVP · Level 3
Find the solution of the differential equation that satisfies the given initial condition. \( \dfrac{d L}{d t} = k L^2 \ln t \), \(\quad L(1) = -1\)
19 Separable Equations - Applications · Level 3
Find an equation of the curve that passes through the point \((0, 2)\) and whose slope at \((x, y)\) is \(\dfrac{x}{y}\).
20 Separable Equations - Applications · Level 3
Find the function \(f\) such that \(f'(x) = x f(x) - x\) and \(f(0) = 2\).
21 Separable Equations - Substitution · Level 4
Solve the differential equation \(y' = x + y\) by making the change of variable \(u = x + y\).
22 Separable Equations - Substitution · Level 4
Solve the differential equation \(x y' = y + x e^{\dfrac{y}{x}}\) by making the change of variable \(v = \dfrac{y}{x}\).
23 Separable Equations - Existence · Level 3
(a) Solve the differential equation \(y' = 2x \sqrt{1 - y^2}\).
(b) Solve the initial-value problem \(y' = 2x \sqrt{1 - y^2}\), \(y(0) = 0\), and graph the solution.
(c) Does the initial-value problem \(y' = 2x \sqrt{1 - y^2}\), \(y(0) = 2\), have a solution? Explain.

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24 Separable Equations - Graphing · Level 3
Solve the equation \(e^{-y} y' + \cos x = 0\) and graph several members of the family of solutions. How does the solution curve change as the constant \(C\) varies?
25 Separable Equations - IVP · Level 3
Solve the initial-value problem \(y' = \dfrac{\sin x}{\sin y}\), \(y(0) = \dfrac{\pi}{2}\), and graph the solution (if your CAS does implicit plots).
26 Separable Equations - Graphing · Level 3
Solve the equation \(y' = \dfrac{x \sqrt{x^2 + 1}}{y e^y}\) and graph several members of the family of solutions (if your CAS does implicit plots). How does the solution curve change as the constant \(C\) varies?
27 Separable Equations - CAS · Level 3
(a) Use a computer algebra system to draw a direction field for the differential equation. Get a printout and use it to sketch some solution curves without solving the differential equation.
(b) Solve the differential equation.
(c) Use the CAS to draw several members of the family of solutions obtained in part (b). Compare with the curves from part (a). \(y' = y^2\)

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28 Separable Equations - CAS · Level 3
(a) Use a computer algebra system to draw a direction field for the differential equation. Get a printout and use it to sketch some solution curves without solving the differential equation.
(b) Solve the differential equation.
(c) Use the CAS to draw several members of the family of solutions obtained in part (b). Compare with the curves from part (a). \(y' = x y\)

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29 Orthogonal Trajectories · Level 3
Find the orthogonal trajectories of the family of curves. Use a graphing device to draw several members of each family on a common screen. \(x^2 + 2y^2 = k^2\)
30 Orthogonal Trajectories · Level 3
Find the orthogonal trajectories of the family of curves. Use a graphing device to draw several members of each family on a common screen. \(y^2 = k x^3\)
31 Orthogonal Trajectories · Level 3
Find the orthogonal trajectories of the family of curves. Use a graphing device to draw several members of each family on a common screen. \(y = \dfrac{k}{x}\)
32 Orthogonal Trajectories · Level 3
Find the orthogonal trajectories of the family of curves. Use a graphing device to draw several members of each family on a common screen. \(y = \dfrac{1}{x + k}\)
33 Integral Equations · Level 4
An integral equation is an equation that contains an unknown function \(y(x)\) and an integral that involves \(y(x)\). Solve the given integral equation. [Hint: Use an initial condition obtained from the integral equation.] \(y(x) = 2 + \displaystyle\int_{2}^{x} [t - t y(t)] d t\)
34 Integral Equations · Level 4
An integral equation is an equation that contains an unknown function \(y(x)\) and an integral that involves \(y(x)\). Solve the given integral equation. \(y(x) = 2 + \displaystyle\int_{1}^{x} \dfrac{d t}{t y(t)}\), \(\quad x > 0\)
35 Integral Equations · Level 4
An integral equation is an equation that contains an unknown function \(y(x)\) and an integral that involves \(y(x)\). Solve the given integral equation. \(y(x) = 4 + \displaystyle\int_{0}^{x} 2t \sqrt{y(t)} d t\)
36 Separable Equations - Applications · Level 4
Find a function \(f\) such that \(f(3) = 2\) and \((t^2 + 1) f'(t) + [f(t)]^2 + 1 = 0\), \(\quad t \neq 1\) [Hint: Use the addition formula for \(\tan(x + y)\) on Reference Page 2.]
37 Separable Equations - Circuits · Level 3
Solve the initial-value problem in Exercise 9.2.27 to find an expression for the charge at time \(t\). Find the limiting value of the charge.
38 Separable Equations - Cooling · Level 3
In Exercise 9.2.28 we discussed a differential equation that models the temperature of a 95 degrees C cup of coffee in a 20 degrees C room. Solve the differential equation to find an expression for the temperature of the coffee at time \(t\).
39 Separable Equations - Learning Model · Level 3
In Exercise 9.1.15 we formulated a model for learning in the form of the differential equation \( \dfrac{d P}{d t} = k(M - P) \) where \(P(t)\) measures the performance of someone learning a skill after a training time \(t\), \(M\) is the maximum level of performance, and \(k\) is a positive constant. Solve this differential equation to find an expression for \(P(t)\). What is the limit of this expression?
40 Separable Equations - Chemical Reactions · Level 4
In an elementary chemical reaction, single molecules of two reactants A and B form a molecule of the product C: \(A + B \rightarrow C\). The law of mass action states that the rate of reaction is proportional to the product of the concentrations of A and B: \( \dfrac{d [C]}{d t} = k [A][B] \) Thus, if the initial concentrations are \([A] = a\) moles/L and \([B] = b\) moles/L and we write \(x = [C]\), then we have \( \dfrac{d x}{d t} = k(a - x)(b - x) \)
(a) Assuming that \(a \neq b\), find \(x\) as a function of \(t\). Use the fact that the initial concentration of C is 0.
(b) Find \(x(t)\) assuming that \(a = b\). How does this expression for \(x(t)\) simplify if it is known that \([C] = \dfrac{1}{2} a\) after 20 seconds?

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41 Separable Equations - Chemical Reactions · Level 4
In contrast to the situation of Exercise 40, experiments show that the reaction \(H_2 + B r_2 \rightarrow 2 H B r\) satisfies the rate law \( \dfrac{d [H B r]}{d t} = k [H_2][B r_2]^{\dfrac{1}{2}} \) and so for this reaction the differential equation becomes \( \dfrac{d x}{d t} = k(a - x)(b - x)^{\dfrac{1}{2}} \) where \(x = [H B r]\) and \(a\) and \(b\) are the initial concentrations of hydrogen and bromine.
(a) Find \(x\) as a function of \(t\) in the case where \(a = b\). Use the fact that \(x(0) = 0\).
(b) If \(a > b\), find \(t\) as a function of \(x\). [Hint: In performing the integration, make the substitution \(u = \sqrt{b - x}\).]

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42 Separable Equations - Heat Transfer · Level 4
A sphere with radius 1 m has temperature \(15^{\circ}.c\). It lies inside a concentric sphere with radius 2 m and temperature \(25^{\circ}.c\). The temperature \(T(r)\) at a distance \(r\) from the common center of the spheres satisfies the differential equation \( \dfrac{d^2 T}{d r^2} + \dfrac{2}{r} \dfrac{d T}{d r} = 0 \) If we let \(S = d \dfrac{T}{d} r\), then \(S\) satisfies a first-order differential equation. Solve it to find an expression for the temperature \(T(r)\) between the spheres.
43 Separable Equations - Mixing Problems · Level 3
A glucose solution is administered intravenously into the bloodstream at a constant rate \(r\). As the glucose is added, it is converted into other substances and removed from the bloodstream at a rate that is proportional to the concentration at that time. Thus a model for the concentration \(C = C(t)\) of the glucose solution in the bloodstream is \( \dfrac{d C}{d t} = r - k C \) where \(k\) is a positive constant.
(a) Suppose that the concentration at time \(t = 0\) is \(C_0\). Determine the concentration at any time \(t\) by solving the differential equation.
(b) Assuming that \(C_0 < \dfrac{r}{k}\), find \(\operatorname*{lim}\limits_{t \rightarrow \infty} C(t)\) and interpret your answer.

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44 Separable Equations - Mixing Problems · Level 3
A certain small country has \$10 billion in paper currency in circulation, and each day \$50 million comes into the country's banks. The government decides to introduce new currency by having the banks replace old bills with new ones whenever old currency comes into the banks. Let \(x = x(t)\) denote the amount of new currency in circulation at time \(t\), with \(x(0) = 0\).
(a) Formulate a mathematical model in the form of an initial-value problem that represents the "flow" of the new currency into circulation.
(b) Solve the initial-value problem found in part (a).
(c) How long will it take for the new bills to account for 90% of the currency in circulation?

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45 Separable Equations - Mixing Problems · Level 3
A tank contains 1000 L of brine with 15 kg of dissolved salt. Pure water enters the tank at a rate of 10 L/min. The solution is kept thoroughly mixed and drains from the tank at the same rate. How much salt is in the tank (a) after \(t\) minutes and (b) after 20 minutes?
46 Separable Equations - Mixing Problems · Level 3
The air in a room with volume 180 m\({}^3\) contains 0.15% carbon dioxide initially. Fresher air with only 0.05% carbon dioxide flows into the room at a rate of 2 m\({}^3\)/min and the mixed air flows out at the same rate. Find the percentage of carbon dioxide in the room as a function of time. What happens in the long run?
47 Separable Equations - Mixing Problems · Level 3
A vat with 500 gallons of beer contains 4% alcohol (by volume). Beer with 6% alcohol is pumped into the vat at a rate of 5 gal/min and the mixture is pumped out at the same rate. What is the percentage of alcohol after an hour?
48 Separable Equations - Mixing Problems · Level 4
A tank contains 1000 L of pure water. Brine that contains 0.05 kg of salt per liter of water enters the tank at a rate of 5 L/min. Brine that contains 0.04 kg of salt per liter of water enters the tank at a rate of 10 L/min. The solution is kept thoroughly mixed and drains from the tank at a rate of 15 L/min. How much salt is in the tank (a) after \(t\) minutes and (b) after one hour?
49 Separable Equations - Physics · Level 4
When a raindrop falls, it increases in size and so its mass at time \(t\) is a function of \(t\), namely, \(m(t)\). The rate of growth of the mass is \(k m(t)\) for some positive constant \(k\). When we apply Newton's Law of Motion to the raindrop, we get \((m v)' = g m\), where \(v\) is the velocity of the raindrop (directed downward) and \(g\) is the acceleration due to gravity. The terminal velocity of the raindrop is \(\operatorname*{lim}\limits_{t \rightarrow \infty} v(t)\). Find an expression for the terminal velocity in terms of \(g\) and \(k\).
50 Separable Equations - Physics · Level 4
An object of mass \(m\) is moving horizontally through a medium which resists the motion with a force that is a function of the velocity; that is, \(m \dfrac{d^2 s}{d t^2} = m \dfrac{d v}{d t} = f(v)\) where \(v = v(t)\) and \(s = s(t)\) represent the velocity and position of the object at time \(t\), respectively.
(a) Suppose that the resisting force is proportional to the velocity, that is, \(f(v) = -k v\), \(k\) a positive constant. Let \(v(0) = v_0\) and \(s(0) = s_0\) be the initial values of \(v\) and \(s\). Determine \(v\) and \(s\) at any time \(t\). What is the total distance that the object travels from time \(t = 0\)?
(b) For larger values of \(v\) a better model is obtained by supposing that the resisting force is proportional to the square of the velocity, that is, \(f(v) = -k v^2\), \(k > 0\). Let \(v_0\) and \(s_0\) be the initial values of \(v\) and \(s\). Determine \(v\) and \(s\) at any time \(t\). What is the total distance that the object travels in this case?

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51 Separable Equations - Biology · Level 4
Allometric growth in biology refers to relationships between sizes of parts of an organism (skull length and body length, for instance). If \(L_1(t)\) and \(L_2(t)\) are the sizes of two organs in an organism of age \(t\), then \(L_1\) and \(L_2\) satisfy an allometric law if their specific growth rates are proportional: \( \dfrac{1}{L_1} \dfrac{d L_1}{d t} = k \dfrac{1}{L_2} \dfrac{d L_2}{d t} \) where \(k\) is a constant.
(a) Use the allometric law to write a differential equation relating \(L_1\) and \(L_2\) and solve it to express \(L_1\) as a function of \(L_2\).
(b) In a study of several species of unicellular algae, the proportionality constant in the allometric law relating \(B\) (cell biomass) and \(V\) (cell volume) was found to be \(k = 0.0794\). Write \(B\) as a function of \(V\).

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52 Separable Equations - Tumor Growth · Level 4
A model for tumor growth is given by the Gompertz equation \( \dfrac{d V}{d t} = a (\ln b - \ln V) V \) where \(a\) and \(b\) are positive constants and \(V\) is the volume of the tumor measured in mm\({}^3\).
(a) Find a family of solutions for tumor volume as a function of \(t\).
(b) Find the solution that has an initial tumor volume of \(V(0) = 1\) mm\({}^3\).

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53 Separable Equations - Biology · Level 4
Let \(A(t)\) be the area of a tissue culture at time \(t\) and let \(M\) be the final area of the tissue when growth is complete. Most cell divisions occur on the periphery of the tissue and the number of cells on the periphery is proportional to \(\sqrt{A(t)}\). So a reasonable model for the growth of tissue is obtained by assuming that the rate of growth of the area is jointly proportional to \(\sqrt{A(t)}\) and \(M - A(t)\).
(a) Formulate a differential equation and use it to show that the tissue grows fastest when \(A(t) = \dfrac{1}{3} M\).
(b) Solve the differential equation to find an expression for \(A(t)\). Use a computer algebra system to perform the integration.

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54 Separable Equations - Physics · Level 5
According to Newton's Law of Universal Gravitation, the gravitational force on an object of mass \(m\) that has been projected vertically upward from the earth's surface is \(F = \dfrac{m g R^2}{(x + R)^2}\) where \(x = x(t)\) is the object's distance above the surface at time \(t\), \(R\) is the earth's radius, and \(g\) is the acceleration due to gravity. Also, by Newton's Second Law, \(F = m a = m\left(d \dfrac{v}{d} t\right)\) and so \(m \dfrac{d v}{d t} = - \dfrac{m g R^2}{(x + R)^2}\)
(a) Suppose a rocket is fired vertically upward with an initial velocity \(v_0\). Let \(h\) be the maximum height above the surface reached by the object. Show that \(v_0 = \sqrt{\dfrac{2 g R h}{R + h}}\) [Hint: By the Chain Rule, \(m\left(d \dfrac{v}{d} t\right) = m v\left(d \dfrac{v}{d} x\right)\).]
(b) Calculate \(v_e = \operatorname*{lim}\limits_{h \rightarrow \infty} v_0\). This limit is called the escape velocity for the earth.
(c) Use \(R = 3960\) mi and \(g = 32\) ft/s\({}^2\) to calculate \(v_e\) in feet per second and in miles per second.

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